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& X0 [: ]9 V; K7 f( X6 d! k% H
/ e+ R# [& u9 t! V1 C$ z. s8 Q( a通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
5 m7 z/ J6 q: P' R7 u* g4 \! j+ G: J5 ^/ o, D
假设大路开这样的路:
+ i( _6 c# { i
0 F# V6 b. s' \ 12121212121212121212121212121212。
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* `" d4 m, J# f% w0 b) e 按2珠路,就是BPBPBPBPBP。
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- S L# A7 \( ~' I2 }- ] 如果我们去掉第一口,就会出现完全相反的结果:0 E# r0 _+ i2 ]4 C" b) u7 Y
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21212121212121212121212121212121。
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变成了PBPBPBPBPB。) u: e% o+ H, q; @$ M n
% w0 s4 X7 A" r, [1 M2 V) @5 E5 t
如果我们再去掉一口,又返回第一种情况了。! ^ ?3 J3 w* i( p8 ]+ B
7 {. j; E" r" o! B; C+ Z 所以每一条大路,按2珠路排列,有2种不同的路数。
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& y. ]0 |/ e; O/ g( t y7 y 再举一个列子:
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7 a+ H8 V+ v4 q6 Z5 z; K 大路:122122122122122122。
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* p7 ^0 ?) b% \$ E% X 按三珠路排列:
3 y- u" J+ f( q6 w4 s" S8 i$ ]
0 X) R7 ~3 S8 E 122,122,122,122,122,122。9 a6 {1 Q5 Z- P8 g' y, M+ q! Z
' g. Q, V3 w$ a1 E 去掉第一口,变成:0 T- [8 Q( T& r3 n n
1 W t$ q0 C8 k 221,221,221,221,221,去掉前2口,变成:
3 U- a2 X9 z; u6 O/ R' O2 d
2 o" o6 W, `( R4 R! d) D$ v 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。( s) j: S. D7 f7 B
1 U0 I L3 g* I2 l4 R! c 同理:按N珠路排列,有N种不同的路数。2 v5 \) e/ A2 }, e
0 f; ~+ H" @' R2 s$ D G( z 我提出这个的意义在于:
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。% T8 Q0 p, C/ p& R/ }# V
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2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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