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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。+ x+ q5 s$ x, |6 g/ F5 ~8 b
8 j( j, {) v8 |
假设大路开这样的路:
* R6 i3 L1 r( G; R; y" Z, a; b {& G7 e6 U/ E7 {; t/ F
12121212121212121212121212121212。6 F. }' v# X M5 J6 i" r9 M
# @) s: H8 n9 i" x* V) g5 w
按2珠路,就是BPBPBPBPBP。& p# @& _; w! ^6 g$ r/ K
) w8 Y7 ]: M2 M0 c 如果我们去掉第一口,就会出现完全相反的结果:0 @- B! ~! \3 j9 b/ e% S! U
5 `# Y d, m9 M" j3 w
21212121212121212121212121212121。
]8 U! ]& p6 V+ B. F! v3 r# j. a o. b$ g, }; T
变成了PBPBPBPBPB。2 k4 k" e- C0 e& c. n' e
. }8 ]; S6 i* y3 |6 h' {
如果我们再去掉一口,又返回第一种情况了。
# W: S, q+ x9 P i0 r
* r3 [; T( A: M$ _1 F7 w9 x1 h5 b 所以每一条大路,按2珠路排列,有2种不同的路数。' z# F. W9 h9 F
, @$ F' A* U7 d/ X7 ~5 i7 F; T
再举一个列子:
7 r: }* H9 g# O# Z" v7 z5 N. c/ U9 s, f: x; P
大路:122122122122122122。/ y6 a! j$ m J) G" U9 K$ s
( h( t5 Z) b* X
按三珠路排列:' ?& y7 D9 A) t7 o# \9 ~8 S# H
% O8 G6 H, I) h. o5 R" L D8 a! x 122,122,122,122,122,122。1 i" ~- o1 W9 d/ ~, {
9 ?0 g a" c0 ^6 \/ Y7 C% e5 g: J
去掉第一口,变成:9 z; X4 R: j! u# q* ]' Q. P6 W
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221,221,221,221,221,去掉前2口,变成:
- v& |/ B5 U! A9 v
4 W& j6 w2 `8 y. t: i 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。5 h( ~9 c: P, O3 D, n1 ^
8 ]8 A4 t- @) Q- Y5 }- N* G 同理:按N珠路排列,有N种不同的路数。
5 m# e+ G# L" h5 o
1 l7 Q' ?& [8 U4 y0 D 我提出这个的意义在于:8 ^( x8 M2 {' l: u/ U# A
6 o; M/ n; ~+ l# y9 _+ N R0 _4 l 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。" D! P5 Q9 N6 S) Z
' W" y% n6 P( m& E" ]
2、为三多理论提供了下注的多面性奠定基础。
" R: h1 t6 S$ I& H4 I8 V9 |$ ^/ D$ J0 w" ]
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。; S: a$ N* \6 [; {4 J2 p1 i- d
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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