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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。8 W- o! \; D) U# j* _) W
* H8 L) \5 p. R7 c% c q* b, q3 I 假设大路开这样的路:
6 J G9 w% s( ?9 W; O
0 z$ {& o5 W' a2 q 12121212121212121212121212121212。
+ l* i( v9 Y8 m4 D8 K4 J8 \; |: C% s# {* e( k
按2珠路,就是BPBPBPBPBP。2 n( B! p& I4 Z7 j- h' v
% u8 W2 h$ O( `* r- Q8 l 如果我们去掉第一口,就会出现完全相反的结果:6 r/ T2 B1 o5 k. ?
2 Q2 O" F6 I% V7 ]- g8 o 21212121212121212121212121212121。+ _: ]# g& I* f3 p4 w! z
' I8 q* z4 T7 k# p1 W2 I, S, ?2 M1 Q 变成了PBPBPBPBPB。
/ H# q+ }; l9 \( C* h( V$ r( [( a
如果我们再去掉一口,又返回第一种情况了。; d* s$ {2 Z. a9 ~* @
& d% W7 a! t: b+ u) ?$ x. l" p7 y
所以每一条大路,按2珠路排列,有2种不同的路数。4 k9 t3 W* w4 j. q' I
0 x6 T5 e: q' F- a
再举一个列子:
1 W6 D0 S3 B4 G Y% _7 X, L! z. C9 N
大路:122122122122122122。! J* S. ^1 k, Q: T$ _
0 V! x8 G3 J7 \) O9 w 按三珠路排列:
6 Z6 i; `, f! A, s- K% p2 p
6 t" j [" G7 j/ T/ |5 Q 122,122,122,122,122,122。
* U& Y* G4 K8 Q8 j/ d/ i. ^! x# ?8 A
去掉第一口,变成:
: r% m# P G. p2 y. `# b# w3 c/ x6 W5 F$ Q3 N
221,221,221,221,221,去掉前2口,变成:
; {( x) j* K0 ]1 ^5 h$ r L9 w# j- ]& F
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。% s9 f3 \/ T* E$ @7 a, Q
# X4 }* Q% A; T
同理:按N珠路排列,有N种不同的路数。, x. Y- D3 X/ q0 Z) D9 F
4 u3 L& E/ c- \$ V3 \4 H3 g4 H
我提出这个的意义在于:
! a ^1 [4 |+ W( Z b0 b; w O% j6 D% ~! _- d
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
$ A1 R: | d2 |! P8 z
4 H$ f4 l7 Z; l6 v 2、为三多理论提供了下注的多面性奠定基础。3 N b, u" [6 N% i
, E& X) x4 k8 h0 W3 u( t+ [; G 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。8 E! L% W* u/ l3 ~' |
: ?# _; U4 Q, a/ O7 F t" h. b
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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