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首先,第一种是运用上期期号的个位数加1后的尾数,作为本期排除的蓝球尾数。来举个例子看看,比如我们要分析双色球游戏第83期的蓝球号码,那么,就上期期号的个位数也就是2,加上1,等于3,那么,当期可以排除的蓝球尾数就是3了,结果,在第83期中开出的蓝球是奖号04。, M& x2 @* O: R3 @
第二种是运用上两期蓝球相加的和,作为本期排除的蓝球,注意,在得数大于16的时候,要减去16。还是来举例看看。比如我们要分析第89期的蓝球号码,用上两期的蓝球号码,分别是06和02相加,得数是8,那么08就是当期可以排除的蓝球号码;最后,在89期的摇奖活动中开出的蓝球号码是04。
) e' w# r% N% [, R: q7 B+ N再来看下面一种方法。运用上一期中第1位的红球号码加3,得数就是本期中可以排除的蓝球号码。还是来看一个例子。比如我们要分析第91期的蓝球号码,先找到上期也就是第90期中第1位的红球号码,当期开出的第1位的红球号码是07,然后,就用7加上3,得数是10,那么,10就是在第92期中可以排除的蓝球号码了;最后当期的蓝球是以奖号04开出的。
' w4 I0 \& X+ n, N2 z第四种方法是用上一期蓝球号码的个位和十位互换位置,换位后的号码就是当期可以排除的蓝球号码,需要注意的是,如果互换位置后的号码大于16的话,就要减去16。比如我们要分析第82期蓝球号码,先看一下第81期开出的蓝球,是奖号03,十位和个位互换位置后是30,然后用30减去16,等于14,那么,14就是第83期可以被排除的蓝球号码,最后,当期开出的蓝球是02。1 b' g$ K% J) h: c
第五种方法是用上上期的蓝球号码除3后取余数,再加上期蓝球,最后的得数就是当期可以排除的蓝球。我们来举例看看,比如我们在分析第91期的蓝球号码时,先找出上上期也就是第89期的蓝球04除3,余数是1,再用1加上期也就是第90期的蓝球号码14,最后的得数是15,那么,15就是在第92期中可以排除的蓝球,最后,当期开出的蓝球号码是04。* p+ J" D% S7 q+ y. ~2 H u
再来看最后一种方法,用上两期蓝球的尾数分别相加和相减,所得值左右各取3位,最后,不在这个范围内的同尾号可以全部作为排除的尾数。
& n3 x! |" z/ ~还是以第92期蓝球号码为例,来看看这种方法的具体操作。首先将上两期的蓝球尾数4和4相加等于8,取左右各3位是5、6、7、8、9、0、1;再用上两期的蓝球尾数相减等于0,取左右各3位是7、8、9、0、1、2、3;可以看出,两组尾数中,没有发生同尾号的分别是5、6、2、3,那么,当期中应该不会开出尾数是2、3、5、6的奖号,也就是说可以排除奖号02、03、05、06、12、13、15以及16;结果当期开出的蓝球号码是04
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