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$ o( G, q) F Z1 U4 q7 M$ F
D% M6 k, q! ~5 N通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
( f/ q7 ?. U7 _0 }
5 l8 W( z# h/ v$ P. ?) B 假设大路开这样的路:: z( e) K* r7 l
" O' }; A$ u) q% a' C; O+ V
12121212121212121212121212121212。
3 V9 {! l3 z/ `- j8 _7 a
. L3 S- U# _4 _ 按2珠路,就是BPBPBPBPBP。
4 W3 D1 Y0 ~& t: _. Z* v) |; H# ?1 W8 b2 m) [6 t
如果我们去掉第一口,就会出现完全相反的结果:) ^+ l) F2 b' z2 ~' m0 L; d7 C1 R
: g$ \4 |; X( X$ l" u! ^- }
21212121212121212121212121212121。+ ^4 u, j/ q% O9 c/ c1 U8 u
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变成了PBPBPBPBPB。; ?, m b8 G; @% m0 p
: Y& I0 y4 a6 }. @
如果我们再去掉一口,又返回第一种情况了。
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+ M; p4 |9 h% W6 k) z. K 所以每一条大路,按2珠路排列,有2种不同的路数。
$ _, v7 k; a! i' k, v2 ]
9 ~* Z5 ~/ e% S 再举一个列子:
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1 B$ V+ j E2 L' R7 v 大路:122122122122122122。
9 \! O/ b- h- h' {2 A
' C# a- o6 i% T 按三珠路排列:
( i# J( A: b1 M2 o- q$ b" `
# H( c) B0 z) H. Y( \ 122,122,122,122,122,122。
# s! g4 r; G- V/ I. R( R' m2 \$ \+ e+ a2 a# G% W# h3 v# G
去掉第一口,变成:9 U. O1 ~9 y( {; u
/ C3 o& N; j* p. ^3 A, T+ Z, `8 ]
221,221,221,221,221,去掉前2口,变成:
! ^4 N! Q5 G( z! k
9 S7 ^# i' o9 k$ c 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。) m- B" R7 U. y
6 A3 S: N7 @; L7 W 同理:按N珠路排列,有N种不同的路数。
+ h) o7 R4 f/ O5 j9 ~$ ~: S% P3 l* y
我提出这个的意义在于:# h l2 M: a0 U
; M3 h/ r, r- l 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。3 k! S/ }8 d- A1 p3 \" B
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2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。2 \8 Z7 K. i- S( x0 U
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