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, c% b- n# H! ^5 v% G6 i0 v( o" }! l: f通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。* c6 S! R& r2 X, J* N) y
0 |$ B( q; x5 p8 c9 Y' U! q 假设大路开这样的路:
4 Q9 E- u0 L# \1 T8 I% o; X, z+ t* ?7 y7 M8 ~. t
12121212121212121212121212121212。+ [+ O: g4 U! ^5 X
! f, Y" L1 K2 x, P0 G% l
按2珠路,就是BPBPBPBPBP。
& ?0 M8 q' }/ A3 L
! n" t# R5 x: Y5 [4 V- M 如果我们去掉第一口,就会出现完全相反的结果:
- K3 \- F& q8 F0 A
: C* y- p) `1 t* u' u/ V! x6 i 21212121212121212121212121212121。: a4 {; p& P, I B- D
$ x6 A6 T2 T9 D- B: q' h7 Q 变成了PBPBPBPBPB。
- R* b. X, y" B# _; k, f- j4 H( R6 U9 ~7 n
如果我们再去掉一口,又返回第一种情况了。
) a6 g7 K, w) }! y/ |+ Z
3 I5 _5 e: V9 K 所以每一条大路,按2珠路排列,有2种不同的路数。% z" @1 P& H3 v9 e# @
# h( p5 A$ O. Y* ]$ `) b 再举一个列子:
/ c6 @5 [" n, j( v
P+ U2 M4 @# F) ~3 b8 _ 大路:122122122122122122。2 U; v; \$ }! j4 \
. h, e! N& s( f c9 u
按三珠路排列:8 z. ?+ Y0 o3 z* |$ l
# {1 M7 w# T! c3 I 122,122,122,122,122,122。
4 P: c) s9 N& G' w# i# t6 f% ^& w' Y
% T; j& o" [% D 去掉第一口,变成:! |: c9 Z7 ]* B
0 P3 @; J, Z1 j, ^# [ 221,221,221,221,221,去掉前2口,变成:% }. x) I5 }1 U/ \& C3 B
' J+ N4 v5 l2 K
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。' ^$ C* [7 r+ h: H
& Y* n( E+ U* {% c/ R. E; n 同理:按N珠路排列,有N种不同的路数。, [' R# ?# {, z4 ?- {" ~0 Y
& o1 V+ U* e& \$ Q0 t0 J0 {4 P; u 我提出这个的意义在于:
7 M* C# W' N* _$ G
$ v& y. {! Y. z' z# c4 D 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。& P0 a0 e: J7 {; H" c0 P- J
& Q& R8 c. B: K5 p+ F 2、为三多理论提供了下注的多面性奠定基础。
8 X5 {0 T7 ?# l8 y' i4 c; c
P2 b: u* `3 P- b 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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