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[lastpost] => 2754081 【星宝】8月4日投注流水2433元 1754245314 豪开心
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。5 s N/ W" Z/ [( B# i
一般来说,) Z/ R% K% Z( G r0 k
二连赢的概率是25%1 g* | J1 s# Q( F2 n" a' X9 ?- {9 d
三连赢的概率是12.5%
- m8 I- ~ v% `9 @7 ~0 `& t8 ` 四连赢的概率是6.25%! W( L' D5 _: r2 J8 m
……4 f8 u# f7 f" r( Y2 y
十连赢的概率是0.09765625%
, V& r0 R6 A/ z; r 这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
( p- V1 M6 z3 q1 H0 g/ v. t! o 百家乐的真实概率含义是:
+ G$ n5 S5 `8 k7 c; F. v 假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球9 ]! ^- T8 g, B! Z" L+ B: H+ R
1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
$ h4 U8 [$ N2 x f) }; k7 s* A 你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
h! y: M, ~2 K' m9 t8 f 你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
U% k+ f P2 _ Y 另外一个说法是,6 P J( L& ^7 M- @2 n( |8 y1 o
1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
, M6 G9 u1 m: E 2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
2 Q/ c. Q$ [9 C2 n3 e, s* r' F3 o 再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。- x. T# C# H" \& d. M2 v1 Z& A* p4 W
平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。
. } _) F: O, k: y' V/ E4 m 对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
! m2 @3 q4 Q* F9 ] D+ K8 X h* K: B 举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。9 X2 F3 K8 G8 L+ _( C6 N
第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
8 r9 C, J2 Z9 q 第三,凯利公式的问题在于:形而上学。) q" s" Z' b) g6 _5 t, E0 w
首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
8 U$ j: ~( W& u0 n9 C; f U/ ?$ i 事实上,你玩的时候,基本上每次都能打到。
P; j a9 O" C- L: Y( Y 因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。 |
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