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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
3 N- t2 Z: q* h' q2 _; v) z9 T 一般来说,
, S7 ]' O" q% Q( ^6 O 二连赢的概率是25%4 X* D8 v, o1 f( i$ O; I. a
三连赢的概率是12.5%4 s+ f$ _0 l2 {# w
四连赢的概率是6.25%3 D* N+ |# H; |
……
+ g& B+ o: b. t0 ]5 v! _: Y, b 十连赢的概率是0.09765625%- s( @" H2 y+ t' e o
这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
$ B' ?8 ]7 _7 F6 H; `& H6 U# m 百家乐的真实概率含义是:
) u2 M: o" [2 n2 J! _0 `6 L M 假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球9 z. g6 D: N& I) {+ u: }
1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。& ^& H& |6 P' d; M$ {$ V- L9 ]
你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。4 M% Y& I# P0 c4 S
你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。$ \1 @$ c$ B! E0 W4 D8 s
另外一个说法是,
+ n1 ?! G% v2 i) u5 I$ ]: l; t 1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
, }9 \) b, t' L/ p 2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。! K( J( f; ^8 Y4 B( C' V0 z) @
再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。4 N( P& q8 j( h# ]
平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。
3 ?% d2 @* {- k& v: K7 r 对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。* ]2 L6 b2 X- i( |
举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。/ D# c4 Z, f4 _ p; |! o
第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化 f% ^/ R0 ~6 T* Q. H
第三,凯利公式的问题在于:形而上学。! U2 z# M# r- t8 G# J. X/ t
首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
$ i1 F, X; ?; } 事实上,你玩的时候,基本上每次都能打到。! W; ^7 ] U( P; f( p
因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。 |
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