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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。
2 k! _4 X4 t S/ b$ i
; z9 L S( R# @) T; H/ v$ R5 Z! w: Y 用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的）
8 b; A; f6 p0 h4 t- `. B' r( j' ~ |5 L4 S
第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）3 F! w+ r- p2 M7 ]/ ^; C
& @, f# E E0 k3 ~% f
第二行：O X X O O OX O X （第二行开始出现洞）' H. ]+ j# l5 k9 b- p7 B
8 p/ X; K; i% i0 t* f( o3 P/ F
第三行：O X O X X V/ x I! J$ R% k( X" Q2 L8 i
O. \5 h) O% e5 Q) N# [ 第四行：O X X
8 E* t: C- {3 B
) t, x; ?, i7 Q; A# U+ r 第五行： X- I: h8 J2 T; A; B0 q& w
7 A4 B* c% D( K( F 那么新写出来的大路是怎么样的呢？
% o! h- S2 I5 y5 j: Z: u; N' d
2 A6 x: Z& H5 h/ t0 D( u. V 记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。
; s3 i/ C r$ e; E& u% k6 x! x% \5 i5 o% r
如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）+ x1 A$ d, r6 K$ [& E S
" {5 T3 ? t' Y" n% e+ S 第一行：OXXOXOXO OXOOX（第一行不再是单跳了）' k; S" q$ L: ]% ^
3 T% f% E3 o. c0 H$ i8 X! y 第二行：OOXXXOOX XXXXX （第二行也是全满的）$ ~4 z4 Q1 H4 K( I5 G) F
& V" `- \. x. O3 j d: z 第三行：OX OX XO XOOX （第三行才出现洞）6 j7 Z* ^% {. H: O. _* G
6 |0 O: C. O E1 [0 z7 L! r 第四行：O XO O XXX 3 o* U1 ?2 P U `
" m5 K/ k7 A+ n/ i$ s; |$ |0 n 第五行： O
% l! a% L H9 P8 X( C( g! P, w/ r
4 `9 m2 A9 K' I: Z 通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。
8 C' d) S5 D+ U5 ]4 x. j' L: g6 R2 L# R# n
大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。" a% y" n! Z9 U0 k
1 }: n# o6 t* { 通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。5 g" G0 D( U8 t1 b
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