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6 @5 ~( y% C. y5 e5 S4 s4 l# a# ]( k/ M
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
; t) f& l1 j+ M; G$ c* g
2 A8 y/ q! O% D+ M; s 假设大路开这样的路:3 f( ^+ s' C- J! O0 H& A
6 \) d( Z0 l% o1 n+ U7 d: y 12121212121212121212121212121212。( K* @3 k0 S' \* d/ f3 P
" K& m4 L6 q% P; W/ R! M. @ 按2珠路,就是BPBPBPBPBP。
* Y5 T) h/ g* R% X
& r4 f* o4 w: Y% m 如果我们去掉第一口,就会出现完全相反的结果:8 ]. D- F7 C( i( H7 h6 }) a% E
4 k7 `2 D/ D3 ?1 Y# f 21212121212121212121212121212121。! z. d) v' C, d- p' n
7 p6 ]. w5 [; ~ 变成了PBPBPBPBPB。
4 X* Z- r/ [* {) G
* p- Y2 l( C9 i 如果我们再去掉一口,又返回第一种情况了。
' B- x! M: K* Z, d" v3 i* i8 b) ^% j& { c( g' s. g- A
所以每一条大路,按2珠路排列,有2种不同的路数。
3 C1 P* o2 Q5 y( U* o8 ]! R! J9 Q; T- I$ n, P# n, J5 [! I
再举一个列子:
9 y0 N% g' k Y4 U
5 J. n; I% K6 y+ z* e% ~6 K 大路:122122122122122122。 }( j& Q, H+ r
4 I# v9 @/ |( o5 O4 O8 ~ C. W- ` 按三珠路排列:+ v: C. u |4 [; ?! z
8 Z/ y! Q+ ]$ U" G- ~
122,122,122,122,122,122。
3 _7 F9 t- k6 A7 X2 \
. R |. h: Z+ Y4 ~$ @1 e" V3 ` 去掉第一口,变成:- g5 N) J- o2 a5 @
. I7 ^* x- Z0 A3 r
221,221,221,221,221,去掉前2口,变成:
. x# ]# i5 v; v2 n6 J% Y4 v8 }$ v" I( R s" S. `) B2 \3 Y
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。 H* H5 p1 v0 |7 `/ s7 P0 g
' r& h$ i: @- y
同理:按N珠路排列,有N种不同的路数。9 U; t0 C. P- ?% c1 W5 A& n2 ]
: p! n& _6 U) c5 Z. c% ?. N: P6 O 我提出这个的意义在于:
+ k+ o- ^' U% l* C8 E
$ b2 n0 t T/ F' n 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
9 f& z' ^& O% {; J- O! i% B/ L9 U0 {1 [3 L; S: O
2、为三多理论提供了下注的多面性奠定基础。. b" L4 e2 b6 A/ t0 G! z
6 |/ I/ B6 \1 _' T# d 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
4 R. x4 r2 ]4 L/ C- s* O
4 m! z5 `* X e; i& ~, F- Q) Q6 p3 }) P* X" L" r, o4 T
0 ^# M5 _* h, b& s1 }/ T% q
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