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[lastpost] => 2809413 【星宝】2月26日投注流水151189元 1772086787 rainwang
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。1 q/ D: I. _3 x- E, y5 ]9 v1 ~
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一般来说,$ F. c& ], L' e+ n' b
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二连赢的概率是25%4 [, O2 u+ |8 U# C- ^/ ]" h1 h
. e1 |( a# B* A% o7 j8 v三连赢的概率是12.5%6 {0 ^! k- z6 i2 z# Y
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四连赢的概率是6.25%$ C9 d7 Q- l7 s3 C/ |6 V6 e
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……
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1 D' A( M, P/ g( h, G6 g! Z* J十连赢的概率是0.09765625%$ k$ @$ M5 I" Z
# j4 S# q O, N" Y2 W5 I8 s1 X这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。( I" U2 a9 H# T3 Y, n3 Y
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百家乐的真实概率含义是:% r3 ?3 Y. b, M7 [: [1 C
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
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/ [+ N8 n. K. Z0 q# @& T& i5 a: C你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。" D7 `$ O& M( c- O7 A
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。& J2 w4 s/ J A- |2 i, E6 v
& I2 j! r; m; b( S另外一个说法是,3 x' J+ m" T$ [7 l5 A w
' @3 x1 O. k! ]/ t3 T9 |% ?1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。" y/ ^7 y5 R0 E+ b- F
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。( U2 ^3 j' e7 p3 y. k+ Y/ V$ j- ^
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。* j7 k8 B. Z& ^1 Z: U2 t- L
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。- c/ d. t1 p/ M2 q! @
$ E, y3 ~# v8 [/ ?$ V第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化1 J2 W4 T" M! P2 r3 T6 t* O, b
, ]0 [7 Y1 q! q( Y3 N( `5 [第三,凯利公式的问题在于:形而上学。
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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: Y8 ?) I6 d* q9 @6 Q3 d, u# z0 M事实上,你玩的时候,基本上每次都能打到。
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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