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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。5 x! Q. E9 A8 x$ Z' i" u/ `2 p
0 f9 I# }1 q0 D1 q 假设大路开这样的路:
, O$ Q: G5 F' ?- O+ c, X
$ V: Z: g5 \- T" ` 12121212121212121212121212121212。
: K0 k2 r! E* m3 e+ [1 S) Z# ]& i4 m9 }9 [
按2珠路,就是BPBPBPBPBP。
% i p6 b" x8 ]. n2 o2 X6 p5 ^5 X5 y, u" V% _7 g: x
如果我们去掉第一口,就会出现完全相反的结果:9 u8 I& m9 [5 t8 L2 |4 u
7 a4 k: m0 a2 `1 M 21212121212121212121212121212121。, N" [: O" A9 y
: d: k8 Z* X, T0 C( i 变成了PBPBPBPBPB。
5 ?( R4 l2 Y4 m# w) t* T' i
- N0 a: _. F; ?+ C4 T 如果我们再去掉一口,又返回第一种情况了。
' m9 ]4 J* L1 ?; v' f/ a+ y, [% G
/ k7 T5 R( N2 _* q# _2 i 所以每一条大路,按2珠路排列,有2种不同的路数。: G' s' K! F- } l7 Z, u! o- `
E# _7 w5 L6 `/ E$ O
再举一个列子:4 B! y! l' c, z+ K: U4 u
, ?. S6 `1 ~, a/ \, j* s3 r1 Q
大路:122122122122122122。
* u9 }5 j5 U* E3 v% f X( z3 G7 }& E0 s1 @* n# W$ Q; @/ ~; z
按三珠路排列:0 n0 T+ W; d: O, a, y* n
- O) [3 r3 y7 {4 ]& V, y J/ h 122,122,122,122,122,122。$ ?" S r5 a" J0 ^$ s
9 S1 W. z& W: g- n 去掉第一口,变成:' U4 D) E: x% N
0 E0 c, }$ k4 q) s" W' ]( W 221,221,221,221,221,去掉前2口,变成:
4 v# N+ A+ E; O( b' ^% c( A
0 W. [2 a3 G8 o6 C$ h 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。9 x- E4 l. p0 R, B k
; w) ?1 }5 a4 ^& B7 j8 b 同理:按N珠路排列,有N种不同的路数。 ^+ u. o6 ]9 P7 y5 p# U
u. o" N; M3 |: e( E- L/ K- I8 ~ 我提出这个的意义在于:% y2 s+ l: i% q- l4 m
1 w) i8 o# l7 S# M4 u8 g
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。! s! E* q* n( @$ U6 Y' ?
! x" z% b! O# a9 R/ t 2、为三多理论提供了下注的多面性奠定基础。4 I; A7 s) c: ]' j& y
* l, ]4 |' d" s" U1 b0 S 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
7 j$ h! m; g7 I7 u$ N; ^
+ T f" x2 V- q& v Q& _' K, F |
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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