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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
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发现了一个有趣的现象，# ?0 n# c( ^+ E9 M8 z8 W. G! \
每一条大路，/ g. v9 q) ^ D ?6 D, N
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
% j6 {1 |. {. j, J) Y( x按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z+ r. s! L3 u6 f6 M+ u9 ?1 C
按4珠路排列，有4种不同的路数" ?2 b4 C0 C8 R* _1 }0 B$ q$ S
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
& ?! |' A0 Q+ G% P什么意思呢，可能大家一时不清楚，8 Q P8 Q- M! T2 a$ O& A; s
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
+ O, \" D6 X2 s$ N( S7 Q* x假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u* ~4 ^) m0 _1 B \
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h4 G3 V( M- d7 \3 p6 e" K; p
够极端了吧
, n# g. a* O& Z+ s' [' N9 v1 `% E按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F4 A7 y9 P. @* g; v& r0 S
如果我们去掉第一口，就会出现完全相反的结果：3 X+ r( n* P0 b+ k. j8 `2 K( c/ R
21212121212121212121212121212121: Y+ a v6 C3 F* p% |
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
. s. g _* W% W9 m$ H: N如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O" I5 w2 H# {+ G9 i
所以每一条大路，! R6 V# q$ h. c; z% O
; F/ y! s; c4 @3 e按2珠路排列，有2种不同的路数。
' w( W* T; k1 r$ X5 c* |) k/ ~再举一个列子：3 D, d* F, F7 [" S6 C5 O; k
大路：122122122122122122。。。
* {$ l( C7 Q/ U& r: J2 z8 M按三珠路排列：$ g3 ~3 T6 m4 K8 k; p( c) ^. |8 S/ A
122，122，122，122，122，122。。。
6 D0 y, f" \$ w, w9 F% }去掉第一口，变成：6 G2 V! \" L' c" k: d" M0 D$ t; z/ K: x; ?6 X4 l
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M: }: Q$ z3 k% R& _+ k
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
3 c. E5 T. m; V3 ?8 D- x( I212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
1 ]9 G7 ?, S1 E4 l# k, ]3 `$ R去掉3口，又返回122，122，122，了. l3 D% |9 g; }8 @* Q- i1 S1 o
所以每一条大路，$ C1 Y" w9 `/ v% ?
按3珠路排列，有3种不同的路数。# O7 `2 O$ w8 c
同理：按N珠路排列，有N种不同的路数。" P: R' r8 W, u: Y6 V4 d
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O" G" B+ Z; L" Y% w+ u8 G$ ?( c
字串83 L: R) G1 V- s2 Y+ Y/ v y9 ^6 J; u& h1 w5 \
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1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
: x U" G1 X6 A6 G2、为三多理论提供了下注的多面性奠定基础。
5 y$ E& E" M% o1 I7 L3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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