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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
: _2 H4 L* v, W, {* b& |; K# P6 J& o7 ^& c; H9 v" H
发现了一个有趣的现象，2 ?% t3 E4 a* ?7 w
每一条大路，: t% o. m& S- R$ I. A) G @
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
. j! I& q+ A J" u按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
5 s1 e- G( n* E2 y8 f- `$ H2 j! X按4珠路排列，有4种不同的路数) I" ]) i9 d4 S# D1 N/ V
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C# U/ ] z G# \# n6 m9 p ]$ n# r
什么意思呢，可能大家一时不清楚，3 |& m, V$ h2 N9 x
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
, k& P" X; C: T8 R" z! c假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u" G$ D/ Y% C2 I t& g# Y
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
9 h0 m: W$ y7 V够极端了吧
, D$ u( Q" J* A# T3 ~4 p& E4 q% s6 d按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
. q' ]0 ~3 v* l# a- e. f2 R/ ^如果我们去掉第一口，就会出现完全相反的结果：
2 x$ W. p& P4 Z& R21212121212121212121212121212121 f! e$ x1 O* n" A2 `- T- k+ d
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
6 E7 `* Q/ \4 w/ p+ Y. ]) a2 c% s) J如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
7 u: u: }7 E& [! ^# o. _所以每一条大路，! R6 V# q$ h. c; z% O* ^. j' c& q9 z! r
按2珠路排列，有2种不同的路数。
7 ?) Y* k4 v: r. Z3 u* ]& J再举一个列子：/ y/ w1 T$ p) S% ?2 y3 N
大路：122122122122122122。。。
: ~- Y G" w6 k S# U按三珠路排列：0 R1 B T2 D; G" d- k: Q
122，122，122，122，122，122。。。+ d, N( ^) i9 f$ u3 e/ K
去掉第一口，变成：6 G2 V! \" L' c" k: d
+ I: |6 |, v# T. Y9 \221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
7 t: d6 p- F0 b! i去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
) g. ?0 f/ D+ |" c212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
' G9 |' ]- w+ s. ~# Q: h去掉3口，又返回122，122，122，了) M# m! F! Y' A0 F0 X7 F9 N
所以每一条大路，; R3 d5 T; R/ s. g
按3珠路排列，有3种不同的路数。( p. Z) S! k$ A C4 x
同理：按N珠路排列，有N种不同的路数。 V0 D; H/ n1 o# _6 _- r
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
+ [) Y# x, O% r! v! n) ^0 n) q字串83 L: R) G1 V- s2 Y+ Y) Y9 b& C: ]8 ~& s) w
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
6 f: S; k$ `$ Z/ z1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |2 B6 `) k, j I( a
2、为三多理论提供了下注的多面性奠定基础。
% o0 ^/ o2 A4 w0 ?* o+ H3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.5 {+ J6 D- x' m( d
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