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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O6 y U( H0 t3 A1 k3 G: l0 ^: X
! O1 h0 M& s9 \+ D& C4 K
发现了一个有趣的现象，
, w6 v) I) ]2 w7 a每一条大路，
}" s2 {+ \- k: W, l+ ~按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f# d, R1 D3 j% M! r% {! A, I
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
2 |4 _+ n9 \) I, @) j6 ]按4珠路排列，有4种不同的路数
. [" y$ A* a8 \$ s+ k2 e按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
& t6 `2 C+ W% V% S什么意思呢，可能大家一时不清楚，
5 z" J! @* u( g j2 v: R5 i O. K我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l$ u. x! ^+ K3 n
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u' p# k7 E( H+ u( j! y
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
* I" ^& l" n2 |$ |, m, v- ]% z够极端了吧
* `" f. N- ?8 d9 d( X; j3 A3 [7 x按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
) S1 @- L& ~; e0 B如果我们去掉第一口，就会出现完全相反的结果：& ]& ]& }, x5 C: U$ L
21212121212121212121212121212121' `4 [; r) H0 z0 \; z* r
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C- }+ h1 @, a! O
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O6 t( {- W" i+ n! Y! m+ q
所以每一条大路，! R6 V# q$ h. c; z% O
; p. g: [) u, Y- p$ S* I按2珠路排列，有2种不同的路数。* x' q5 T# J( c1 ?2 C9 y" |! t
再举一个列子：
8 }+ d" ^) Y; L大路：122122122122122122。。。
( K* U5 h; J1 l6 c2 I% ~按三珠路排列：
" ^4 h; S [% u3 \122，122，122，122，122，122。。。
) h' q; S, n4 l9 e去掉第一口，变成：6 G2 V! \" L' c" k: d
+ z( g+ t* \6 \% T# O221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M3 B% @, j$ W% }' a `) j4 J' P. G; J
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
& k' {' v; i) J212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
) B1 I' p% o4 a; V1 i去掉3口，又返回122，122，122，了
/ d: m" ^" d9 E+ D% s6 }所以每一条大路，
& y k- z5 C" }1 O5 y1 ~/ H按3珠路排列，有3种不同的路数。
' d7 @4 H" u& K0 A6 J% s$ w同理：按N珠路排列，有N种不同的路数。
. ]7 X- a. B* L* o我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O4 [6 D( |/ t' Q+ g" v- k
字串83 L: R) G1 V- s2 Y+ Y
4 `6 l+ J4 b" p- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
) [" t3 \+ _) }+ M, g H1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |1 c4 a- s! b. F
2、为三多理论提供了下注的多面性奠定基础。
# m/ X2 ]( b; t' U3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.$ \7 W, N4 ? s4 P, t* ]
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