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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
0 o0 c) c. j, K; H. z0 Q+ j- ~' x2 X$ g Y
发现了一个有趣的现象，
6 V1 g4 b* p3 D$ {" D* P9 m/ \每一条大路，0 ]% K6 f& A* y" R; l
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f% m6 j: W. K% a2 k7 v, ?
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z4 e3 P; E! E* Y( e
按4珠路排列，有4种不同的路数
; d8 `: v2 z- w. r按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C/ P0 u% y, \" ]& z- `3 I, J
什么意思呢，可能大家一时不清楚，
/ l1 C" L. a) f' r4 S我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l3 v! s4 X! \6 k1 _3 N
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u3 I9 s$ G5 z( {. i6 j% I
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h& `1 U% p& E. M o' e& R. S
够极端了吧9 B- c( ~, ?' @% y4 ]
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
) F- d$ K& a, q- \9 d如果我们去掉第一口，就会出现完全相反的结果：
3 R& D) w1 h# O. Z21212121212121212121212121212121
3 _# e* x4 H3 U; T; b; }5 X变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
8 N2 \1 x/ v% y如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
. D# Z/ m5 J; n. t: w; Q所以每一条大路，! R6 V# q$ h. c; z% O( R2 T u9 A1 L; J! ^1 Q0 W
按2珠路排列，有2种不同的路数。
6 U/ }+ Q" z- t1 q( s再举一个列子：, y6 q5 X/ Z# Q
大路：122122122122122122。。。# v( J; H: Q3 V8 F' A6 `, e' c
按三珠路排列：; v" y1 }( Q8 U' a, D* _. s# o3 j1 o
122，122，122，122，122，122。。。
N! N5 |2 }1 w% ?: V去掉第一口，变成：6 G2 V! \" L' c" k: d4 L7 L2 L; Q: z% v2 W
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
: w4 a% S( W: X/ z, M) G去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W( s1 o( b2 J9 t/ K* u' Y7 z" s
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
7 T% @9 [! _ Y去掉3口，又返回122，122，122，了0 f8 a% W7 U* v" v9 |, ^: ~3 n+ c
所以每一条大路，7 o N7 P4 x+ R, B( k
按3珠路排列，有3种不同的路数。
/ i% }0 C3 r1 E% g3 t同理：按N珠路排列，有N种不同的路数。+ }$ g, X# h' F; {5 ?: \/ N( I$ c
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
5 p/ n! Q9 S, K$ Z字串83 L: R) G1 V- s2 Y+ Y( i& h* d7 \1 g q4 g( l2 P* v( U
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
1 J6 N2 C1 \ d, \" z1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
& E- t+ F n* ~. v( w. C2、为三多理论提供了下注的多面性奠定基础。; H2 j9 _) U, H$ @+ M
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
5 c$ N3 K3 k8 R* {$ Q0 H* T |
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