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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
$ x* L% c# {: Y9 C( ?) \. R9 J$ Y7 X9 R! H3 n% x
发现了一个有趣的现象，% m1 n. l! A1 i. e; f
每一条大路，
. E8 B4 L0 g* L按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f5 k% l7 c/ W4 Z1 A5 J
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z X5 y" ]. `; W# Y+ |3 W
按4珠路排列，有4种不同的路数
% u5 q/ a) b8 F1 V7 I按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
0 @9 `" p% L3 z: Q" f1 c; Y什么意思呢，可能大家一时不清楚，8 r5 \1 B# V2 t' \
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
! l! Z$ V8 }& F! _3 s# I5 f假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u+ [) x$ ]5 w9 p+ j" I0 h g) v" @
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h2 Y* o; x: j' H# V7 h4 ]8 p
够极端了吧
% q& `# f" J) g按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F: V9 V4 R4 f7 G( _/ q5 e! W1 z) o
如果我们去掉第一口，就会出现完全相反的结果：! K+ k$ c* o" P; i: V
21212121212121212121212121212121 n& M0 B' w) h; Y$ v
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
" x# x8 p- i" @1 G( Q, {如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O$ k7 ^# a, D- F. W2 r
所以每一条大路，! R6 V# q$ h. c; z% O
( U$ S+ r; D0 s" Y4 O/ P7 ~ I3 K8 ?按2珠路排列，有2种不同的路数。: R' F! H8 n9 O+ S! o, r% H
再举一个列子：
" n( I/ h* M) k# l" [大路：122122122122122122。。。8 s f9 D/ _- c9 T) a- o5 z N5 D9 z
按三珠路排列：- y" c" B6 f1 M
122，122，122，122，122，122。。。5 p$ p: p; k9 a1 H
去掉第一口，变成：6 G2 V! \" L' c" k: d
5 s# W9 f! A" N221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
! f: }0 D% R1 e7 d去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W2 o) J1 x& H# U
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `7 Q3 }1 c H# Y+ D; p9 i+ C
去掉3口，又返回122，122，122，了
8 a8 ~* i5 j8 e7 B! C$ l; r5 I所以每一条大路，
: q. v4 V6 D# B& I按3珠路排列，有3种不同的路数。
+ V, y0 J4 c, O# h+ b同理：按N珠路排列，有N种不同的路数。
; y+ M& A6 G7 g- u/ @, h0 ]我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
$ ^( a2 S1 v: { E' P+ m字串83 L: R) G1 V- s2 Y+ Y8 u& o. e& G6 N4 t! g2 K
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
! H7 _' H" r' W0 a$ n1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
% F9 E, r3 s' u# ^9 W1 p! Q0 E- P& a2、为三多理论提供了下注的多面性奠定基础。8 `+ X6 K. i$ z- O+ m* `
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
3 m0 M" l ]/ Z0 { \" v( G' O) t |
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