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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
5 v2 f. ^) N$ W/ \: k! p! B8 K* X0 `% U2 Z. C$ v4 H+ y
发现了一个有趣的现象，/ Q" h9 h0 t+ p# N$ n" l7 d. s) J
每一条大路，$ Y+ U, m/ E5 g
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
% ]. r/ E8 w$ ~- a$ @按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z) v9 D! J( D7 Q. t
按4珠路排列，有4种不同的路数1 E2 B, ^* x5 H A$ T, q
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
2 H2 R. H5 Q% k& X. ?0 n1 {' T8 r: }什么意思呢，可能大家一时不清楚，
( ^" W: x& x0 A我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l H! U ]3 m' C; {; e
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u9 L+ B( v) Y/ f' i; |) w o$ x( u& r+ K
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h, C' ?3 D# D* R
够极端了吧
- {" f5 u& \7 A4 t( v: L3 \! ]2 q按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
' I$ g, c+ x l1 H; b如果我们去掉第一口，就会出现完全相反的结果：% Y* l; B# B% Y7 A8 D
21212121212121212121212121212121& q+ n0 s: M1 d/ R+ D! W) n
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C: G& x( g% u* d U0 ?
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
. T" w1 U5 [. C, F所以每一条大路，! R6 V# q$ h. c; z% O
2 [7 J4 z. \) S: Y按2珠路排列，有2种不同的路数。
( b# g8 y! g1 w, j; G0 K+ d再举一个列子：
2 ~) g. j5 N; S+ Z" ^大路：122122122122122122。。。! F, y. O$ g8 j7 R0 l7 o6 U
按三珠路排列：
7 c% q4 z! U% ^ i$ _6 ?122，122，122，122，122，122。。。3 m6 Q& W( {" U9 B
去掉第一口，变成：6 G2 V! \" L' c" k: d f6 {. W4 p& j/ {0 u( m
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
9 W% {, h; ~$ J去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
$ U( x9 D+ t' \* I9 e212，212，212，212，212，: y& l, B; I6 e- m. J# c) `' F" O$ q3 t8 l, E v2 d
去掉3口，又返回122，122，122，了
5 E6 P# ~1 x! o- G3 C }/ S所以每一条大路，) I: \6 _( A* \ Y
按3珠路排列，有3种不同的路数。0 l* n* Z( a; |" p! @2 O: u% S
同理：按N珠路排列，有N种不同的路数。. e5 @3 p0 P9 `0 L @$ T
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O' S; { P! d' e, w
字串83 L: R) G1 V- s2 Y+ Y' n# f! ~" V$ [ g" q( \8 _
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
0 i7 m D' [- s0 `4 y! Z1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |' Y; ?8 e, p, \& t0 w; V
2、为三多理论提供了下注的多面性奠定基础。
) J5 M% t* p0 ^3 Z5 _- c' n3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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