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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
1 y( u! v) O% J
- z( R$ r: t9 C& N发现了一个有趣的现象，, S. j6 R$ B- A, u7 l+ K* M! S# H
每一条大路，( O% G6 s' G" r1 L. p& x
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f* W r( `: W8 _' Y) S V
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
. N5 U8 @% c F! N# ^. O# R按4珠路排列，有4种不同的路数
2 w. m( A2 V4 `; l8 c按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C, r$ T5 C, M/ [' r% o0 ^+ _9 }
什么意思呢，可能大家一时不清楚，
$ e: F; h. p* y, |8 e我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l5 k5 n- S% e- I% G
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
1 b3 V6 `: x5 ]" ~5 D; [8 d8 m- D; s12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h1 }: @8 E: }; F/ Y% s* P {
够极端了吧
! B% @/ \0 M8 R4 a* I" [2 a按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F5 a6 V, R; w; ~6 Z
如果我们去掉第一口，就会出现完全相反的结果：
- ]3 l" A" a" i2 J% T, t8 X- o21212121212121212121212121212121; ^$ M3 Q I) l0 }
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
* R: q6 ?7 w E3 J如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
* a8 L& Q$ n3 s: z. h- i* X, p所以每一条大路，! R6 V# q$ h. c; z% O7 L: h$ n2 @ v! N
按2珠路排列，有2种不同的路数。, k- p1 J3 T+ T4 \+ a& a
再举一个列子：
+ b7 ^ D x9 ]大路：122122122122122122。。。
6 q4 H9 }4 v( ?3 T% ]) ]按三珠路排列：+ }5 h( K0 Q/ f7 k" l
122，122，122，122，122，122。。。
3 P3 E9 y% D! L/ i7 S去掉第一口，变成：6 G2 V! \" L' c" k: d# d) }) q- S" I& }9 m1 `0 x
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M2 ], w0 [9 p, b& z& K
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W. W% E% g0 Q) J9 |
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `( D$ |( R4 B# d+ L
去掉3口，又返回122，122，122，了# |' r% ~- X5 V+ C! O% q* ^
所以每一条大路，
! N8 G. \; H" v( G' z# X按3珠路排列，有3种不同的路数。
+ f* `8 n0 P# {0 k% W同理：按N珠路排列，有N种不同的路数。
! S# n4 o# L9 }) T; x! V我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
" e- x" b' D. L) ]' G0 K' e; k字串83 L: R) G1 V- s2 Y+ Y# P7 v7 Y1 t7 s" S
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
! Z+ r4 C X* m$ g; \% G1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
8 J% B. z7 ?( d5 k6 Q* r2、为三多理论提供了下注的多面性奠定基础。
8 B B& T3 \, L( c& M, J; ~0 p3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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