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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
" K1 Q S* q$ N6 O% g; `# n6 V3 k" O6 P
发现了一个有趣的现象，
% y" ?# n5 p. {6 @& x) K每一条大路，
% P$ |: f# X' y6 r按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f9 T( l4 {+ I4 D8 L
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z) i0 x/ C" I# s, ^/ L
按4珠路排列，有4种不同的路数
_. y7 M1 L" v3 a按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C2 D! |; b \* a W0 G4 H) v. D
什么意思呢，可能大家一时不清楚，- q5 k V6 ?0 {' l2 @2 o3 W
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
2 o0 ^) _5 n1 U) n0 D& I5 t假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
% T1 w% \2 {# e6 b0 a12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
% J% a5 u$ ?1 L9 p" \够极端了吧
& ?. ], O. K5 U5 d( Z) M$ g按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F4 C& o, A! n6 U# [: V# y
如果我们去掉第一口，就会出现完全相反的结果：
4 \% U% m) o7 ^# e+ H21212121212121212121212121212121" p: V+ B6 N4 b/ y
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C/ T- C' m+ I6 N! l$ k6 B
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O% L9 w0 U, S0 i9 E2 R8 E/ G; b
所以每一条大路，! R6 V# q$ h. c; z% O
( @4 \/ W( V4 t1 i+ E* Y按2珠路排列，有2种不同的路数。. H9 A# l+ X* G: m' n$ [
再举一个列子：5 \. r5 D; k2 r% C9 w! M4 h/ E
大路：122122122122122122。。。
3 A6 A9 \; v9 n' K; g) v按三珠路排列：. g5 A6 p1 q1 A$ G3 i( O
122，122，122，122，122，122。。。
1 d: q! @; _) V) ?6 {去掉第一口，变成：6 G2 V! \" L' c" k: d: y8 N" g+ A) ^! i. F; p' F" `
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
, }0 b: G# o6 a/ \8 L去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
0 {5 O `6 K* _. U$ b# L212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
1 ^6 H" u6 V1 D& P1 s去掉3口，又返回122，122，122，了
4 d/ N3 j8 W: A @6 s! v所以每一条大路，
5 _. {- V8 o: Y+ w) O" o6 J$ d4 m按3珠路排列，有3种不同的路数。7 S O, {* v. w# D4 k! C
同理：按N珠路排列，有N种不同的路数。
6 i+ n5 ^6 ]: i: D; y我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O& [9 Z" |+ t! V% j, s; a
字串83 L: R) G1 V- s2 Y+ Y5 [+ c" L1 l" }" D" Z2 f" C
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @- E, l6 R4 f: y/ D$ L) d" c1 B
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |- s# B0 d: o7 U& c( ?" S" q
2、为三多理论提供了下注的多面性奠定基础。0 G _8 p, O* X4 G
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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