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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O7 X9 Z7 O8 U8 _ [, q
8 _/ @0 T, \7 Z/ M( B- \
发现了一个有趣的现象，5 J* Q- |3 n8 {# Q- r1 _$ r
每一条大路，
3 f4 {- [! ^/ \: A$ D8 {按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
0 A, Y0 _9 P8 d4 w0 S+ P: d) a" q按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z0 o$ x& l/ \6 o
按4珠路排列，有4种不同的路数
' z# V6 z. H4 j按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
+ A& J- ]3 U, J5 y$ t5 R什么意思呢，可能大家一时不清楚，
" z6 ^3 Z: P6 X% ]1 X; l% H6 w我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
9 H& ?) E* c6 A7 h- v假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u+ K5 `! k5 a2 c& D, |) a. t
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h- M. I- K& o2 M& D
够极端了吧# _& F) u4 ]3 W( ]' T* H6 \! ~
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
) m+ ?% U; t/ @如果我们去掉第一口，就会出现完全相反的结果：8 e; D/ V4 ^6 Q% i
21212121212121212121212121212121
7 H% l- Q' L, D. L' K变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C( d* x; l8 ]+ y; l
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
8 ^) L# r, G2 Z9 _) f+ w所以每一条大路，! R6 V# q$ h. c; z% O
! r/ d! a! ?. `0 h% ?按2珠路排列，有2种不同的路数。
4 O) ^3 ^$ A# ?4 z- |再举一个列子：
7 C* }; a$ \5 D大路：122122122122122122。。。9 T5 C0 @# C0 E* a% j- w0 \
按三珠路排列：
& [! S! m7 H2 B, h2 G: X9 F# d9 ^6 I122，122，122，122，122，122。。。7 g1 T+ T1 S( Z( w+ g+ w, q; u
去掉第一口，变成：6 G2 V! \" L' c" k: d
9 U4 P) {6 c8 j- n221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
; ~/ E( h# O5 E2 z+ b; Z去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
7 z/ K2 v8 f$ t9 F* B212，212，212，212，212，: y& l, B; I6 e- m. J# c) `( f! S+ T' P- ]# r9 G. ?7 P
去掉3口，又返回122，122，122，了
% ?0 |1 ^. h" [" t所以每一条大路，8 y( ?, E8 s& \8 t; h) k. I5 E; {0 v, q
按3珠路排列，有3种不同的路数。
! @- o( D, c0 `! t) k7 k0 n4 j0 f同理：按N珠路排列，有N种不同的路数。; a$ ]$ u1 P6 v' x; D
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O8 t/ o6 q! c* j1 G6 _( {& _( j" }
字串83 L: R) G1 V- s2 Y+ Y# X6 H/ c6 R. r) [/ @ }
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
/ g6 R! \, ?0 Z- Z$ p v: J" Q1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |* I' y5 c' n& I# }" j0 @: O
2、为三多理论提供了下注的多面性奠定基础。) L* X: I( I- J0 }
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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